The command as below:
$ cat /var/log/zimbra.log | awk -F 'from=<' '{print $2}' | awk -F'>' '{print $1}' | sed '/^$/d' | sort | uniq -c | sort -nk1 -r | sed -n '1,6p'Note:
- sed '/^$/d' : To delete only blank lines
- sed -n '1,6p' : To print 1 line to 6 line.
- awk -F 'from=<' '{print $2}' | awk -F'>' '{print $1}' : To print the email of sender address
Thanks for sharing. this is help me
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